Inverse Square Law Worksheet If an x-ray machine operator receives… Inverse Square Law Worksheet If an x-ray machine operator receives an exposure o

Inverse Square Law Worksheet If an x-ray machine operator receives… Inverse Square Law Worksheet If an x-ray machine operator receives an exposure of 200 R/Hr at a distance of 36 inches.  What is the exposure rate if the distance is changed to 72 inches?If the exposure rate was 100 mSv at a distance of 40 inches.  What would be the new exposure rate if the distance was reduced to 20 inches?If the intensity of the exposure was 200 mSv at 60 SID and we change it to 20 SID.  What is the new exposure rate?If everything in problem #3 remained the same except change 60 SID to 20SID and 20 SID to 60. What would be the new exposure rate?If the exposure rate is 90 R/Hr.  At a distance of 30 SID.  What would be the new exposure rate if the distance is changed to 10 SIDCalculate the following using the inverse square law. RadiologyHeat Unit Practice QuestionsSingle phasemA: 125 kVp: 75   Time: 1/18 secmA: 100 kVp: 62   Time: 0.5 secmA: 80 kVp: 58   Time: 1/32 secmA: 130 kVp: 72   Time: 0.9 secmA: 300 kVp: 110   Time: 0.025 secmA: 170 kVp: 64  Time: 0.111 secThree PhasemA: 140 kVp: 78   Time: 1/45 secmA: 50 kVp: 76   Time: 0.02 secmA: 300 kVp: 120   Time: 0.033 secmA: 300 kVp: 110  Time: 1/18 secmA: 250 kVp: 78   Time: 0.002 secmA: 110 kVp: 80   Time: 1/3 secHigh FrequencymA: 150 kVp: 72   Time: 1/60 secmA: 120 kVp: 46   Time: 1/30 secmA: 200 kVp: 56   Time: 0.121 secmA: 100 kVp: 84   Time: 1/45 secmA: 125 kVp: 76   Time: 1/10 sec                            Give the mAs value for the following mA and time combinations:1. 400 mA 1/120 sec2. 600 mA 1/30 sec3. 500 mA 1/5 sec4. 200 mA 3/10 sec5. 50 mA 1/40 sec6. 100 mA 1/15 sec7. 300 mA 1/10 sec8. 100 mA 3/20 sec9. 600 mA 2/5 sec10. 500 mA 1/40 sec11. 300 mA 0.035 sec12. 400 mA 0.025 sec13. 600 mA 0.01 sec14. 500 mA 0.4 sec15. 100 mA 0.01 sec16. 200 mA 0.02 sec17. 300 mA 0.07 sec18. 500 mA 0.35 sec19. 50 mA 0.035 sec20. 600 mA 0.25 secCalculate the following using the inverse square law. I1 10mR         D1 36in       D2 72inI1 150mR      D1 34in        D2 68inI1 45mR        D1 29in       D2 58   Science Biology RMA M34516 Share QuestionEmailCopy link Comments (0)

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Inverse Square Law Worksheet If an x-ray machine operator receives…          Inverse Square Law Worksheet If an x-ray machine operator receives an exposure of 200 R/Hr at a distance of 36 inches.  What is the exposure rate if the distance is changed to 72 inches?If the exposure rate was 100 mSv at a distance of 40 inches.  What would be the new exposure rate if the distance was reduced to 20 inches?If the intensity of the exposure was 200 mSv at 60 SID and we change it to 20 SID.  What is the new exposure rate?If everything in problem #3 remained the same except change 60 SID to 20SID and 20 SID to 60. What would be the new exposure rate?If the exposure rate is 90 R/Hr.  At a distance of 30 SID.  What would be the new exposure rate if the distance is changed to 10 SIDCalculate the following using the inverse square law. RadiologyHeat Unit Practice QuestionsSingle phasemA: 125 kVp: 75   Time: 1/18 secmA: 100 kVp: 62   Time: 0.5 secmA: 80 kVp: 58   Time: 1/32 secmA: 130 kVp: 72   Time: 0.9 secmA: 300 kVp: 110   Time: 0.025 secmA: 170 kVp: 64  Time: 0.111 secThree PhasemA: 140 kVp: 78   Time: 1/45 secmA: 50 kVp: 76   Time: 0.02 secmA: 300 kVp: 120   Time: 0.033 secmA: 300 kVp: 110  Time: 1/18 secmA: 250 kVp: 78   Time: 0.002 secmA: 110 kVp: 80   Time: 1/3 secHigh FrequencymA: 150 kVp: 72   Time: 1/60 secmA: 120 kVp: 46   Time: 1/30 secmA: 200 kVp: 56   Time: 0.121 secmA: 100 kVp: 84   Time: 1/45 secmA: 125 kVp: 76   Time: 1/10 sec                            Give the mAs value for the following mA and time combinations:1. 400 mA 1/120 sec2. 600 mA 1/30 sec3. 500 mA 1/5 sec4. 200 mA 3/10 sec5. 50 mA 1/40 sec6. 100 mA 1/15 sec7. 300 mA 1/10 sec8. 100 mA 3/20 sec9. 600 mA 2/5 sec10. 500 mA 1/40 sec11. 300 mA 0.035 sec12. 400 mA 0.025 sec13. 600 mA 0.01 sec14. 500 mA 0.4 sec15. 100 mA 0.01 sec16. 200 mA 0.02 sec17. 300 mA 0.07 sec18. 500 mA 0.35 sec19. 50 mA 0.035 sec20. 600 mA 0.25 secCalculate the following using the inverse square law. I1 10mR         D1 36in       D2 72inI1 150mR      D1 34in        D2 68inI1 45mR        D1 29in       D2 58                                                              Science                                                Biology                            RMA M34516                                                                      Share QuestionEmailCopy link                              Comments (0)

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